By M. M. Novak (auth.)
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Extra info for Advanced Graphics with the Commodore 128
8 100 110 120 130 140 150 160 170 180 190 200 210 REM GRAPH WITH SCALING II COLOR 1,8: GRAPHIC 1,1 NP=10: DIM XCNP), Y(NP) FOR I=0 TO NP: READ X(I),Y(I) IF X(I)>XX THEN XX=X(I) IF Y(I)>YY THEN YY=Y(I) NEXT FX=319/XX: FY=199/YY DRAW 1,X(0)*FX,199-Y(0)*FY: FOR I=1 TO NP DRAW TO X(I)*FX,199-Y(I)*FY: NEXT DATA 10,11, 45,15, 95,17, 120,26, 133,22, 159,13, 250,9 DATA 259,4, 288,18, 411,20, 513,14 The largest X- andY-coordinates, respectively, are obtained in lines 140 and 150. The scale factors for the x- andy-directions are denoted, in turn, by FX and FY.
This is not a difficult problem to tackle. The simplest way to create a bar is to draw a rectangle using the BOX command. 2. 2 100 110 120 130 REM HISTOGRAM 2 - BAR COLOR 1,8: GRAPHIC 1,1 YC=99: FOR X=10 TO 300 STEP 10: Y=80*SIN(X/10)+YC BOX 1,X,YC,X+7,199-Y: NEXT X This program differs from the previous one only in line 130. The bottom left corner of the bar has coordinates (X, YC), the top right corner (X + 7,199 - Y). The difference in X-coordinates establishes the width of the bar, the difference in Y-coordinates determines its height.
Also, you may have noticed that the line density is not even. In other words, some parts have an abundance of points, while others do not. By decreasing the step size in the loop 120, this problem can be eliminated and you end up with a smooth curve. However, many points are now calculated unnecessarily and it takes much longer to complete the circle. The fault lies with the method chosen- the increment intervals are evenly spaced along the x-axis rather than along the arc of the circle. Angular method Application of this method produces a circle with equally spaced points along the arc.
Advanced Graphics with the Commodore 128 by M. M. Novak (auth.)
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